- Let us consider that the initial temperature or room temperature says 20 degree centigrade and final temperature of armature be 60 degree centigrade.
As
R2 = R1 ( 1 + αt0 )
R20 = R0 ( 1 + 20α0 )
R65 = R0 ( 1 + 65α0 )
Where α0 = 1 / 234.5 ohm / ohm / 0C
Therefore
R65 / R20 = [ R0 ( 1 + 65α0 ) ] / [ R0 ( 1 + 20α0 ) ]
R65 / R20 = [ 234.5 + 65 / 234.5 + 20 ]
R65 = 1.17 R20
- If initial armature resistance at 20 degree centigrade was 1 ohm , it will become 1.17 ohm at 60 degree centigrade.
- It is called as hot armature resistance
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